3.2985 \(\int \frac{\sqrt{2+3 x}}{(1-2 x)^{5/2} (3+5 x)^{3/2}} \, dx\)

Optimal. Leaf size=156 \[ -\frac{214 \text{EllipticF}\left (\sin ^{-1}\left (\sqrt{\frac{3}{7}} \sqrt{1-2 x}\right ),\frac{35}{33}\right )}{847 \sqrt{33}}-\frac{2470 \sqrt{1-2 x} \sqrt{3 x+2}}{27951 \sqrt{5 x+3}}+\frac{214 \sqrt{3 x+2}}{2541 \sqrt{1-2 x} \sqrt{5 x+3}}+\frac{2 \sqrt{3 x+2}}{33 (1-2 x)^{3/2} \sqrt{5 x+3}}+\frac{494 E\left (\sin ^{-1}\left (\sqrt{\frac{3}{7}} \sqrt{1-2 x}\right )|\frac{35}{33}\right )}{847 \sqrt{33}} \]

[Out]

(2*Sqrt[2 + 3*x])/(33*(1 - 2*x)^(3/2)*Sqrt[3 + 5*x]) + (214*Sqrt[2 + 3*x])/(2541*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])
- (2470*Sqrt[1 - 2*x]*Sqrt[2 + 3*x])/(27951*Sqrt[3 + 5*x]) + (494*EllipticE[ArcSin[Sqrt[3/7]*Sqrt[1 - 2*x]], 3
5/33])/(847*Sqrt[33]) - (214*EllipticF[ArcSin[Sqrt[3/7]*Sqrt[1 - 2*x]], 35/33])/(847*Sqrt[33])

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Rubi [A]  time = 0.0528049, antiderivative size = 156, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.179, Rules used = {99, 152, 158, 113, 119} \[ -\frac{2470 \sqrt{1-2 x} \sqrt{3 x+2}}{27951 \sqrt{5 x+3}}+\frac{214 \sqrt{3 x+2}}{2541 \sqrt{1-2 x} \sqrt{5 x+3}}+\frac{2 \sqrt{3 x+2}}{33 (1-2 x)^{3/2} \sqrt{5 x+3}}-\frac{214 F\left (\sin ^{-1}\left (\sqrt{\frac{3}{7}} \sqrt{1-2 x}\right )|\frac{35}{33}\right )}{847 \sqrt{33}}+\frac{494 E\left (\sin ^{-1}\left (\sqrt{\frac{3}{7}} \sqrt{1-2 x}\right )|\frac{35}{33}\right )}{847 \sqrt{33}} \]

Antiderivative was successfully verified.

[In]

Int[Sqrt[2 + 3*x]/((1 - 2*x)^(5/2)*(3 + 5*x)^(3/2)),x]

[Out]

(2*Sqrt[2 + 3*x])/(33*(1 - 2*x)^(3/2)*Sqrt[3 + 5*x]) + (214*Sqrt[2 + 3*x])/(2541*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])
- (2470*Sqrt[1 - 2*x]*Sqrt[2 + 3*x])/(27951*Sqrt[3 + 5*x]) + (494*EllipticE[ArcSin[Sqrt[3/7]*Sqrt[1 - 2*x]], 3
5/33])/(847*Sqrt[33]) - (214*EllipticF[ArcSin[Sqrt[3/7]*Sqrt[1 - 2*x]], 35/33])/(847*Sqrt[33])

Rule 99

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((a + b
*x)^(m + 1)*(c + d*x)^n*(e + f*x)^(p + 1))/((m + 1)*(b*e - a*f)), x] - Dist[1/((m + 1)*(b*e - a*f)), Int[(a +
b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p*Simp[d*e*n + c*f*(m + p + 2) + d*f*(m + n + p + 2)*x, x], x], x] /;
FreeQ[{a, b, c, d, e, f, p}, x] && LtQ[m, -1] && GtQ[n, 0] && (IntegersQ[2*m, 2*n, 2*p] || IntegersQ[m, n + p
] || IntegersQ[p, m + n])

Rule 152

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[((b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/((m + 1)*(b*c - a*d)*(b*e - a*
f)), x] + Dist[1/((m + 1)*(b*c - a*d)*(b*e - a*f)), Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p*Simp[(a*d*f*
g - b*(d*e + c*f)*g + b*c*e*h)*(m + 1) - (b*g - a*h)*(d*e*(n + 1) + c*f*(p + 1)) - d*f*(b*g - a*h)*(m + n + p
+ 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && LtQ[m, -1] && IntegersQ[2*m, 2*n, 2*p]

Rule 158

Int[((g_.) + (h_.)*(x_))/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]*Sqrt[(e_) + (f_.)*(x_)]), x_Symbol]
:> Dist[h/f, Int[Sqrt[e + f*x]/(Sqrt[a + b*x]*Sqrt[c + d*x]), x], x] + Dist[(f*g - e*h)/f, Int[1/(Sqrt[a + b*
x]*Sqrt[c + d*x]*Sqrt[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f, g, h}, x] && SimplerQ[a + b*x, e + f*x] &&
SimplerQ[c + d*x, e + f*x]

Rule 113

Int[Sqrt[(e_.) + (f_.)*(x_)]/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]), x_Symbol] :> Simp[(2*Rt[-((b*e
- a*f)/d), 2]*EllipticE[ArcSin[Sqrt[a + b*x]/Rt[-((b*c - a*d)/d), 2]], (f*(b*c - a*d))/(d*(b*e - a*f))])/b, x
] /; FreeQ[{a, b, c, d, e, f}, x] && GtQ[b/(b*c - a*d), 0] && GtQ[b/(b*e - a*f), 0] &&  !LtQ[-((b*c - a*d)/d),
0] &&  !(SimplerQ[c + d*x, a + b*x] && GtQ[-(d/(b*c - a*d)), 0] && GtQ[d/(d*e - c*f), 0] &&  !LtQ[(b*c - a*d)
/b, 0])

Rule 119

Int[1/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]*Sqrt[(e_) + (f_.)*(x_)]), x_Symbol] :> Simp[(2*Rt[-(b/d
), 2]*EllipticF[ArcSin[Sqrt[a + b*x]/(Rt[-(b/d), 2]*Sqrt[(b*c - a*d)/b])], (f*(b*c - a*d))/(d*(b*e - a*f))])/(
b*Sqrt[(b*e - a*f)/b]), x] /; FreeQ[{a, b, c, d, e, f}, x] && GtQ[(b*c - a*d)/b, 0] && GtQ[(b*e - a*f)/b, 0] &
& PosQ[-(b/d)] &&  !(SimplerQ[c + d*x, a + b*x] && GtQ[(d*e - c*f)/d, 0] && GtQ[-(d/b), 0]) &&  !(SimplerQ[c +
d*x, a + b*x] && GtQ[(-(b*e) + a*f)/f, 0] && GtQ[-(f/b), 0]) &&  !(SimplerQ[e + f*x, a + b*x] && GtQ[(-(d*e)
+ c*f)/f, 0] && GtQ[(-(b*e) + a*f)/f, 0] && (PosQ[-(f/d)] || PosQ[-(f/b)]))

Rubi steps

\begin{align*} \int \frac{\sqrt{2+3 x}}{(1-2 x)^{5/2} (3+5 x)^{3/2}} \, dx &=\frac{2 \sqrt{2+3 x}}{33 (1-2 x)^{3/2} \sqrt{3+5 x}}-\frac{2}{33} \int \frac{-\frac{31}{2}-\frac{45 x}{2}}{(1-2 x)^{3/2} \sqrt{2+3 x} (3+5 x)^{3/2}} \, dx\\ &=\frac{2 \sqrt{2+3 x}}{33 (1-2 x)^{3/2} \sqrt{3+5 x}}+\frac{214 \sqrt{2+3 x}}{2541 \sqrt{1-2 x} \sqrt{3+5 x}}+\frac{4 \int \frac{\frac{605}{2}+\frac{1605 x}{4}}{\sqrt{1-2 x} \sqrt{2+3 x} (3+5 x)^{3/2}} \, dx}{2541}\\ &=\frac{2 \sqrt{2+3 x}}{33 (1-2 x)^{3/2} \sqrt{3+5 x}}+\frac{214 \sqrt{2+3 x}}{2541 \sqrt{1-2 x} \sqrt{3+5 x}}-\frac{2470 \sqrt{1-2 x} \sqrt{2+3 x}}{27951 \sqrt{3+5 x}}-\frac{8 \int \frac{\frac{915}{8}+\frac{3705 x}{4}}{\sqrt{1-2 x} \sqrt{2+3 x} \sqrt{3+5 x}} \, dx}{27951}\\ &=\frac{2 \sqrt{2+3 x}}{33 (1-2 x)^{3/2} \sqrt{3+5 x}}+\frac{214 \sqrt{2+3 x}}{2541 \sqrt{1-2 x} \sqrt{3+5 x}}-\frac{2470 \sqrt{1-2 x} \sqrt{2+3 x}}{27951 \sqrt{3+5 x}}-\frac{494 \int \frac{\sqrt{3+5 x}}{\sqrt{1-2 x} \sqrt{2+3 x}} \, dx}{9317}+\frac{107}{847} \int \frac{1}{\sqrt{1-2 x} \sqrt{2+3 x} \sqrt{3+5 x}} \, dx\\ &=\frac{2 \sqrt{2+3 x}}{33 (1-2 x)^{3/2} \sqrt{3+5 x}}+\frac{214 \sqrt{2+3 x}}{2541 \sqrt{1-2 x} \sqrt{3+5 x}}-\frac{2470 \sqrt{1-2 x} \sqrt{2+3 x}}{27951 \sqrt{3+5 x}}+\frac{494 E\left (\sin ^{-1}\left (\sqrt{\frac{3}{7}} \sqrt{1-2 x}\right )|\frac{35}{33}\right )}{847 \sqrt{33}}-\frac{214 F\left (\sin ^{-1}\left (\sqrt{\frac{3}{7}} \sqrt{1-2 x}\right )|\frac{35}{33}\right )}{847 \sqrt{33}}\\ \end{align*}

Mathematica [A]  time = 0.122889, size = 99, normalized size = 0.63 \[ \frac{\sqrt{2} \left (4025 \text{EllipticF}\left (\sin ^{-1}\left (\sqrt{\frac{2}{11}} \sqrt{5 x+3}\right ),-\frac{33}{2}\right )-494 E\left (\sin ^{-1}\left (\sqrt{\frac{2}{11}} \sqrt{5 x+3}\right )|-\frac{33}{2}\right )\right )-\frac{2 \sqrt{3 x+2} \left (4940 x^2-2586 x-789\right )}{(1-2 x)^{3/2} \sqrt{5 x+3}}}{27951} \]

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[2 + 3*x]/((1 - 2*x)^(5/2)*(3 + 5*x)^(3/2)),x]

[Out]

((-2*Sqrt[2 + 3*x]*(-789 - 2586*x + 4940*x^2))/((1 - 2*x)^(3/2)*Sqrt[3 + 5*x]) + Sqrt[2]*(-494*EllipticE[ArcSi
n[Sqrt[2/11]*Sqrt[3 + 5*x]], -33/2] + 4025*EllipticF[ArcSin[Sqrt[2/11]*Sqrt[3 + 5*x]], -33/2]))/27951

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Maple [C]  time = 0.022, size = 228, normalized size = 1.5 \begin{align*} -{\frac{1}{27951\, \left ( 2\,x-1 \right ) ^{2} \left ( 15\,{x}^{2}+19\,x+6 \right ) }\sqrt{1-2\,x}\sqrt{2+3\,x}\sqrt{3+5\,x} \left ( 8050\,\sqrt{2}{\it EllipticF} \left ( 1/11\,\sqrt{66+110\,x},i/2\sqrt{66} \right ) x\sqrt{3+5\,x}\sqrt{2+3\,x}\sqrt{1-2\,x}-988\,\sqrt{2}{\it EllipticE} \left ( 1/11\,\sqrt{66+110\,x},i/2\sqrt{66} \right ) x\sqrt{3+5\,x}\sqrt{2+3\,x}\sqrt{1-2\,x}-4025\,\sqrt{2}\sqrt{3+5\,x}\sqrt{2+3\,x}\sqrt{1-2\,x}{\it EllipticF} \left ( 1/11\,\sqrt{66+110\,x},i/2\sqrt{66} \right ) +494\,\sqrt{2}\sqrt{3+5\,x}\sqrt{2+3\,x}\sqrt{1-2\,x}{\it EllipticE} \left ( 1/11\,\sqrt{66+110\,x},i/2\sqrt{66} \right ) +29640\,{x}^{3}+4244\,{x}^{2}-15078\,x-3156 \right ) } \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((2+3*x)^(1/2)/(1-2*x)^(5/2)/(3+5*x)^(3/2),x)

[Out]

-1/27951*(2+3*x)^(1/2)*(1-2*x)^(1/2)*(3+5*x)^(1/2)*(8050*2^(1/2)*EllipticF(1/11*(66+110*x)^(1/2),1/2*I*66^(1/2
))*x*(3+5*x)^(1/2)*(2+3*x)^(1/2)*(1-2*x)^(1/2)-988*2^(1/2)*EllipticE(1/11*(66+110*x)^(1/2),1/2*I*66^(1/2))*x*(
3+5*x)^(1/2)*(2+3*x)^(1/2)*(1-2*x)^(1/2)-4025*2^(1/2)*(3+5*x)^(1/2)*(2+3*x)^(1/2)*(1-2*x)^(1/2)*EllipticF(1/11
*(66+110*x)^(1/2),1/2*I*66^(1/2))+494*2^(1/2)*(3+5*x)^(1/2)*(2+3*x)^(1/2)*(1-2*x)^(1/2)*EllipticE(1/11*(66+110
*x)^(1/2),1/2*I*66^(1/2))+29640*x^3+4244*x^2-15078*x-3156)/(2*x-1)^2/(15*x^2+19*x+6)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{3 \, x + 2}}{{\left (5 \, x + 3\right )}^{\frac{3}{2}}{\left (-2 \, x + 1\right )}^{\frac{5}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^(1/2)/(1-2*x)^(5/2)/(3+5*x)^(3/2),x, algorithm="maxima")

[Out]

integrate(sqrt(3*x + 2)/((5*x + 3)^(3/2)*(-2*x + 1)^(5/2)), x)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{\sqrt{5 \, x + 3} \sqrt{3 \, x + 2} \sqrt{-2 \, x + 1}}{200 \, x^{5} - 60 \, x^{4} - 138 \, x^{3} + 47 \, x^{2} + 24 \, x - 9}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^(1/2)/(1-2*x)^(5/2)/(3+5*x)^(3/2),x, algorithm="fricas")

[Out]

integral(-sqrt(5*x + 3)*sqrt(3*x + 2)*sqrt(-2*x + 1)/(200*x^5 - 60*x^4 - 138*x^3 + 47*x^2 + 24*x - 9), x)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)**(1/2)/(1-2*x)**(5/2)/(3+5*x)**(3/2),x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{3 \, x + 2}}{{\left (5 \, x + 3\right )}^{\frac{3}{2}}{\left (-2 \, x + 1\right )}^{\frac{5}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^(1/2)/(1-2*x)^(5/2)/(3+5*x)^(3/2),x, algorithm="giac")

[Out]

integrate(sqrt(3*x + 2)/((5*x + 3)^(3/2)*(-2*x + 1)^(5/2)), x)